Commit 8c49bbf6 authored by Simon Morlat's avatar Simon Morlat

Don't INVITE a new device of a participant if other devices of this same...

Don't INVITE a new device of a participant if other devices of this same participant are in left state.
parent dbee4ba3
......@@ -718,6 +718,7 @@ void ServerGroupChatRoomPrivate::addParticipantDevice (const shared_ptr<Particip
// Nothing to do, but set the name because the user-agent is not known for the initiator device.
} else if (findAuthorizedParticipant(participant->getAddress())) {
bool allDevLeft = !participant->getPrivate()->getDevices().empty() && allDevicesLeft(participant);
* This is a really new device.
......@@ -726,7 +727,12 @@ void ServerGroupChatRoomPrivate::addParticipantDevice (const shared_ptr<Particip
shared_ptr<ConferenceParticipantDeviceEvent> event = qConference->getPrivate()->eventHandler->notifyParticipantDeviceAdded(participant->getAddress(), deviceInfo.getAddress());
setParticipantDeviceState(device, ParticipantDevice::State::ScheduledForJoining);
if (capabilities & ServerGroupChatRoom::Capabilities::OneToOne && allDevLeft){
/* If all other devices have left, let this new device to left state too, it will be invited to join if a message is sent to it. */
setParticipantDeviceState(device, ParticipantDevice::State::Left);
setParticipantDeviceState(device, ParticipantDevice::State::ScheduledForJoining);
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